second dropdown value according to first dropdown using jquery

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<style>
select{
  width: 100px;
  display: block;
  margin: 10px;
}
</style>
<script>
$(document).ready(function(){
  
  $('#one').change(function() {
    $('#two').prop('disabled', this.value == '0');

  
    $("#two option").each(function(){
  
    if($("#one option:selected").val() >= $(this).val())
            $(this).attr("disabled", "disabled");
        else
  
      $(this).removeAttr("disabled");
  
    });
  
  
}).change();



});
</script>
</head>

<body>
<select name="first" id="one">
<option disabled="disabled" selected="selected" value="0">Please</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
<select name="two" id="two">
<option disabled="disabled" selected="selected" value="0">Please</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>

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